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α1 =
F2 = 300,16 lb
α2 =
F3 = 100,16 lb
α3 = =
F4 = 200,16
α4 =
ditanya R
F1x = F1 .cos α1 F1y = F1 .sin α1
= 200,16 . cos = 200,16 .cos
= 200,16 . 1 = 200,16 . 0
= 200,16 = 0
F2x = F2 .cos α2 F2x = F2 . sin α2
= 300,16 .cos = 300,16 .sin
= 300,16 . 0,4067 = 300,16 . 0,9135
= 122,08 = 274,20
F3x = F3 .cos F3x = F3 .sin
= 100,16 . - 0,6293 = 100,16 0,777
= 188,89 = 233,22
F4x = F4 .cos F4x = F4 .sin
= 200,16 .0 = 200,16 .- 1
= 0 = - 200,16
∑Fx = 200,16 + 122,08 + 188,89 + 0
= 511,13
∑Fy = 0 + 274,20 + 233,22 + - 200,16
=307,26
R =
=
=
=
= 596,3745 lb
2) diketahui : R = 1000,16 lb
αR = =
ditanya : F4
F1x = F1 cos F1y = F2x .sin
= 400,16 . 0,4067 = 400,16 .0,9135
= 162,75 = 365,55
F2x = 300,16 .cos F1y = 300,16 .sin
= 300,16 . 0 = 300,16 . 1
= 0 = 300,16 lb
F3x = 400,16 cos F3y = 400,16 .sin
= 400,16 . - 0,515 = 400,16 . - 0,8571
= - 206,08 = - 342,98
F4x = F4 . cos α F4y = F4 sin α
∑Fx = 162,75 + 0 - 206,08 + F4x .cos α
= (F4x .cis α - 43,33)
∑Fy = 365,55 + 300,16 - 342,98 + F4 sin α
= (322,73 + F4 sinα)
R² = (∑Fx)² + (∑ Fy)²
(1000,16)² = (F4x. cos α - 43,33)² + (322,73 + F4y .sin α)²
1000320,03 = (F4x)² cos²α - 86,66 .F4x .cos α + 1877,49 + 104154,65 + 645,46 . F4y.sin α + (F4y)² sin² α
= (F4x)² + (F4y)² - 86,66 F4x .cos α + 645,46 .F4y . sin α + 106032,14
(f4x)² + F4y)² - 86,66.F4x .cos α + 645,46 .F4y sin α = 894287,89
( F4)² + 86,66 .F4 + 645,46 .F4 = 894287,89
(F4)² + 732,12 .F4 = 894287,89
(F4 + 732,12 .F4 - 894287,89 = 0
gunakan rumus ABC