Penjelasan:
P = 200 W
V = 220 V
ΔT = 100°C ‐ 20°C = 80°C
m = 1 liter → 1 kg
c = 1 kal/g°C → 4200 J/kg°C
Lama waktu yang dibutuhkan = _____?
Jawab :
Q = W
m . c . ΔT = P . t
1 . 4200 . 80 = 200 . t
336000 = 200 . t
t = 1680 detik atau 28 menit
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Penjelasan:
P = 200 W
V = 220 V
ΔT = 100°C ‐ 20°C = 80°C
m = 1 liter → 1 kg
c = 1 kal/g°C → 4200 J/kg°C
Lama waktu yang dibutuhkan = _____?
Jawab :
Q = W
m . c . ΔT = P . t
1 . 4200 . 80 = 200 . t
336000 = 200 . t
t = 1680 detik atau 28 menit