Oblicz ile:
a)wynosi y skoro x=9 [cm], a 1/f= 0,102 [1/m]
b) wynosi y skoro x=20 [cm], a 1/f= 0,101 [1/m]
a)
dane:
x = 9 cm = 0,09 m
Z = 1/f = 0,102/m
szukane:
y = ?
f = 1/Z
f = 1/0,102
f = 9,8 m
Z równania soczewki:
1/f = 1/x + 1/y
1/y = 1/f - 1/x
1/y = (x-f)/xf
y = xf/(x-f) = 0,09m*9,8m/(0,09m-9,8m) = 0,882m²/(-9,71m)
y = -0,09 m
y = -9 cm
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b)
x = 20 cm = 0,2 m
Z = 1/f = 0,101/m
f = 1/0,101
f = 9,9 m
y = xf/(x-f) = 0,2m*9,9m/(0,2m-9,9m = 1,98m²/(-9,7m)
y = -0,2 m
y = -20 cm
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a)
dane:
x = 9 cm = 0,09 m
Z = 1/f = 0,102/m
szukane:
y = ?
f = 1/Z
f = 1/0,102
f = 9,8 m
Z równania soczewki:
1/f = 1/x + 1/y
1/y = 1/f - 1/x
1/y = (x-f)/xf
y = xf/(x-f) = 0,09m*9,8m/(0,09m-9,8m) = 0,882m²/(-9,71m)
y = -0,09 m
y = -9 cm
-------------
b)
dane:
x = 20 cm = 0,2 m
Z = 1/f = 0,101/m
szukane:
y = ?
f = 1/Z
f = 1/0,101
f = 9,9 m
y = xf/(x-f) = 0,2m*9,9m/(0,2m-9,9m = 1,98m²/(-9,7m)
y = -0,2 m
y = -20 cm
--------------