jaką krawędź ma sześcienna kostka wykonana ze złota o gęstości 19320kg/m3 jeżeli jej masa-m = 0,5kg?
Pozdrawiam
dane:
d = 19 320 kg/m3
m = 0,5 kg
szukane:
V = ?
a = ?
V = a^3
d = m/V I*V
V x d = m /:d
V = m/d
V = 0,5kg/19320kg/m3 = 0,000026 m3
a = (3)V0,000026 [m]
a = ok.0,3 m
==========
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Pozdrawiam
dane:
d = 19 320 kg/m3
m = 0,5 kg
szukane:
V = ?
a = ?
V = a^3
d = m/V I*V
V x d = m /:d
V = m/d
V = 0,5kg/19320kg/m3 = 0,000026 m3
a = (3)V0,000026 [m]
a = ok.0,3 m
==========