Kawałek metalu o gęstości 7,86*10/3 kg/m3 i masie 5 kg zanurzono w wodzie. Oblicz wartość siły wypory.
dane:
d₁=7,86·10³kg/m³
m=5kg
d₂=1000kg/m³=10³kg/m³
szukane:
F w=?
F w=V·g·d₂
d₁=m/V⇒V=m/d₁
F w=m/d₁·g·d₂
F w=(5kg/7,86·10³kg/m³ )·10N/kg·10³kg/m³
F w=6,36N
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dane:
d₁=7,86·10³kg/m³
m=5kg
d₂=1000kg/m³=10³kg/m³
szukane:
F w=?
F w=V·g·d₂
d₁=m/V⇒V=m/d₁
F w=m/d₁·g·d₂
F w=(5kg/7,86·10³kg/m³ )·10N/kg·10³kg/m³
F w=6,36N