Question

Pd seutas kawat baja dgn pnjang 3m & luas penampang 0,15 cm² dgantungkan sbuah beban massanya 500 kg (g= 9,8m/s²). tentukan :
a. tetapan gaya kawat
b. pertambahan panjang kawat
(modulus elastis baja= 2,0 x 10¹¹ N/m²)

Answer 1

ELASTISITAS x = 3 m A = 0,15x10^-2 m^2 m = 500 kg g = 9,8 m/s^2 E = 2x10^11 N/m^2 ∆x = __? k = __? ∆x = F x / (A E) ∆x = (500x9,8) (3) / ( (0,15x10^-4) (2x10^11) ) ∆x = 0,0049 m k = F / ∆x = mg / ∆x k = 4900 / 0,0049 = 10^6 N/ m Ok ?