Air mengalir melalui pipa mendatar dari penampang besar ke penampang kecil.Luas penampang besar 3 kali luas penampang kecil.Apabila kecepatan di penampang kecil 1m/s, nilai p2-p1 sebesar... N/m^2
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diket :
A1 = A
A2 = 3A
v1 = 1 m/s
ditanya : P2-P1
jawab:
P2-P1 = - 1/2 rho . v1 ( (A1/A2)² - 1)
= - 1/2 . 1000 . 1 ((1/3)² - 1 )
= -500. (1/9 - 9/9)
= -500 . -8/9
= 444,44 N/m²