Oblicz szukane wartości dla sprężyny z ciężarkiem:
k=250Nm
m=150g=0.15kg
g=10m/s²
ω=?
ω=√k/m
ω=√250/0.15=√1666.66
ω=40rad/s
ω=2πf
f=ω/2π
f=40/2*3.14
f=6,5Hz
T=1/f
T=1/6.5=0.15s
Vmax=ωA
Ec=Ep⇒kA²=kx²
mg=kx
x=mg/k
x=0.15*10/250=0.006m-wydluzenie sprezyny
A²=kx²/k
A²=250*0.006²/250
A²=0.000036
A=0.006
Vmax=ωA=40*0.006=0.24M/S
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k=250Nm
m=150g=0.15kg
g=10m/s²
ω=?
ω=√k/m
ω=√250/0.15=√1666.66
ω=40rad/s
ω=2πf
f=ω/2π
f=40/2*3.14
f=6,5Hz
T=1/f
T=1/6.5=0.15s
Vmax=ωA
Ec=Ep⇒kA²=kx²
mg=kx
x=mg/k
x=0.15*10/250=0.006m-wydluzenie sprezyny
A²=kx²/k
A²=250*0.006²/250
A²=0.000036
A=0.006
Vmax=ωA=40*0.006=0.24M/S