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2(3x + 1) - x + 6 = 2(x - 1)
6x + 2 - x + 6 = 2x - 2
5x + 8 = 2x - 2
5x - 2x = -2 - 8
3x = -10
x = - 10/3 ---> Rta
Compruebas:
2(3(-10/3) + 1) - (-10/3) + 6 = 2(-10/3 - 1)
2(-30/3 + 1) + 10/3 + 6 = 2(-13/3)
2(-10 + 1) + 28/3 = -26/3
2(-9) + 28/3 = -26/3
-18 + 28/3 = -26/3
-26/3 = -26/3 --->>> Cumple la igualdad
Entonces podemos decir que el ejercicio fue desarrollado correctamente.