La frecuencia angular del sistema es ω = √(k/m) = 2 π f
f = √(k/m) / (2 π)
f = √(20 N/m / 10 kg) / (2 π)
Saludos.
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Verified answer
La frecuencia angular del sistema es ω = √(k/m) = 2 π f
f = √(k/m) / (2 π)
f = √(20 N/m / 10 kg) / (2 π)
f = 0,225 Hz
Saludos.