Luas selimut tabung 2.200 cm2, sedangkan tingginya 25 cm, berapakah jari-jarinya
udink
L= 2 pi r t = 2200 sehingga akan diperoleh jari-jari (r) = 14
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Swaibatul
L selimut tabung = 2 πrt 2.200 = 2 x 22/7 x r x 25 2.200 = 44/7 x r x 25 2.200 = 1.100/7 x r r = 2.200 : 1.100/7 r = 2.200 x 7/1.100 r = 14 cm
2.200 = 2 x 22/7 x r x 25
2.200 = 44/7 x r x 25
2.200 = 1.100/7 x r
r = 2.200 : 1.100/7
r = 2.200 x 7/1.100
r = 14 cm