Luas selimut tabung 1.884 cm2. jika tinggi tabung 20 cm dan pendekatan phi = 3,14, maka volume tabung itu adalah..
rerena
L selimut tabung = 2.π.r.t 1884=2.3,14.r.20 1884=125,6.r 15=r
Vol. tabung= πr²t 3,14.15².20 3,14.225.20 14130
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RaudhatunSafitri
Diket : L.slimut = 1884 cm^2 , t=20 cm phi=3,14 Dit : Vtbung ..? * L.slimut = 2 x phi x r x t 1884 = 2 x 3,14 x r x 20 1884 = 125,6 x r r = 1884/125,6 = 15 cm * V tbubg = phi x r^2 x t = 3,14 x 15^2 x 20 = 3,14 x 225 x 20 V tbung = 14130 cm^3
1884=2.3,14.r.20
1884=125,6.r
15=r
Vol. tabung= πr²t
3,14.15².20
3,14.225.20
14130
Dit : Vtbung ..?
* L.slimut = 2 x phi x r x t
1884 = 2 x 3,14 x r x 20
1884 = 125,6 x r
r = 1884/125,6 = 15 cm
* V tbubg = phi x r^2 x t
= 3,14 x 15^2 x 20
= 3,14 x 225 x 20
V tbung = 14130 cm^3