Luas selimut kerucut yang keliling alasnya 75,36 cm, tinggi 16cm, dan pendekatan Pi=3,14 adalah?
tantikris43
K = 2 x phi x r 75,36 = 2 x 3,14 x r r = 75,36 : 6,28 r = 12 Luas selimut kerucut = phi x r x s s = akar ( 12x12 +16 x 16 )= akar 400 = 20 Luas selimut kerucut = 3,14 x 12 x 20 = 753,6 cm2
9 votes Thanks 29
wiwied
Diketahui : keliling alas = 75,36 cm t = 16 cm
ditanya : luas selimut kerucut jawab
keliling = 2 x 3,14 x r 75,36 = 6,28 x r r = 75,36 : 6,28 = 12 cm
s² = r² + t² s² = 12² + 16² s² = 144 +256 s² = 400 s = √400 s = 20 cm
luas selimut kerucut = π r s = 3,14 x 12 x 20 = 753,6 cm²
t = 16 cm
ditanya : luas selimut kerucut
jawab
keliling = 2 x 3,14 x r
75,36 = 6,28 x r
r = 75,36 : 6,28
= 12 cm
s² = r² + t²
s² = 12² + 16²
s² = 144 +256
s² = 400
s = √400
s = 20 cm
luas selimut kerucut = π r s
= 3,14 x 12 x 20
= 753,6 cm²