Question

Luas selimut kerucut yang keliling alasnya 75,36 cm, tinggi 16 cm, dan pendekatan phi = 3,14 adalah ...

Answer 1

R= 75,36 / 3,14 / 2
 = 12 cm

garis pelukis (s)= √ 12^2 + 16^2 = √ 144+256 = √400 = 20 cm

L selimut = πrs = 3,14 x 12 x 20 = 753,6 cm2

Answer 2

Keliling alas = 2πr
75.36 = 2 x 3.14 x r
75.36 = 6.28 r
r = 75.36 : 6.28
r = 12 cm
* s = √r² + t²
     = √12² + 16²
     = √144 + 256
     = √400 = 20 cm
#Luas selimut = πrs
= 3.14 x 12 x 20
= 753.6 cm²