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Verified answer
Bab Bangun RuangMatematika SMP Kelas IX
kerucut
1] luas selimut = π x r x s = 924
22/7 x 10,5 x s = 924
33 x s = 924
s = 924 : 33
s = 28 cm
2] luas permukaan = luas alas + luas selimut
= π x r x r + 924
= 22/7 x 10,5 x 10,5 + 924
= 346,5 + 924
= 1.270,5 cm²