Question

Luas selimut kerucut 204,1 cm2. diameter kerucut 10 cm phi= 3,14, berapa tinggi kerucut?

Answer 1

Ls = phi.r.s
204,1 = 3,14.5.s
204,1 = 15,7.s
s = 204,1 ÷ 15,7
s = 13cm
t = (s^2-r^2)^1/2
t = (13^2-5^2)^1/2
t = (169-25)^1/2
t = (144)^1/2
t = 12cm