Penjelasan dengan langkah-langkah:
a) Jari jari :
L = π × r × r
1.386 = 22/7 × r²
r² = 1.386 × 7/22
r² = 441
r = √441
r = 21 Cm
b) Keliling :
= 2 × π × r
= 2 × 22/7 × 21
= 2 × 22 × 3
= 132 Cm
Luas sebuah lingkaran adalah 1.386 cm².Tentukan:
a.jari jari lingkaran,
b. keliling lingkaran!
[tex]L = \pi \: {r}^{2} = 1.386 \\ \frac{22}{7} \times {r}^{2} = 1.386 \\ {r}^{2} = 1.386 \times \frac{7}{22} \\ {r}^{2} = 63 \times 7 \\ {r}^{2} = 441 \\ r = \sqrt{441} \\ r = 21 \: cm[/tex]
[tex]K = 2\pi \: r \\ = 2 \times \frac{22}{7} \times 21 \\ = 2 \times 22 \times 3 \\ = 198 \: cm[/tex]
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Verified answer
Penjelasan dengan langkah-langkah:
a) Jari jari :
L = π × r × r
1.386 = 22/7 × r²
r² = 1.386 × 7/22
r² = 441
r = √441
r = 21 Cm
b) Keliling :
= 2 × π × r
= 2 × 22/7 × 21
= 2 × 22 × 3
= 132 Cm
Penjelasan dengan langkah-langkah:
Luas sebuah lingkaran adalah 1.386 cm².Tentukan:
a.jari jari lingkaran,
b. keliling lingkaran!
[tex]L = \pi \: {r}^{2} = 1.386 \\ \frac{22}{7} \times {r}^{2} = 1.386 \\ {r}^{2} = 1.386 \times \frac{7}{22} \\ {r}^{2} = 63 \times 7 \\ {r}^{2} = 441 \\ r = \sqrt{441} \\ r = 21 \: cm[/tex]
[tex]K = 2\pi \: r \\ = 2 \times \frac{22}{7} \times 21 \\ = 2 \times 22 \times 3 \\ = 198 \: cm[/tex]