Luas persegi panjang ABCD 24 satuan luas dan panjang bc = 6 satuan.kedua diagonal persegi panjang berpotongan di titik E(-1,-1).tentukan koordinat titik A,B,C,D!!!
copodonk
Panjang = 6 = ad berarti lebar = 24/6 = 4 = ab = cd pusat di (-1,-1) A = x = -1 - 4/2 = -3 y = -1 + 6/2 = 2
B = x = -1 + 2 = 1 y = -1 + 3 = 2
C = x = -1 + 2 = 1 y = -1 - 3 = -4
D = x = -1 - 2 = -3 y = -1 - 3 = -4
jadi kordinat a,b,c,d berturut 2 (-3,2), (1,2), (1,-4), (-3,-4)
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subebe
Panjang = bc = 6 lebar = ab = 24 / 6 = 4 besar translasi / perpindahan = (1/2 l , 1/2 p) = (2 , 3)
berarti lebar = 24/6 = 4 = ab = cd
pusat di (-1,-1)
A = x = -1 - 4/2 = -3
y = -1 + 6/2 = 2
B = x = -1 + 2 = 1
y = -1 + 3 = 2
C = x = -1 + 2 = 1
y = -1 - 3 = -4
D = x = -1 - 2 = -3
y = -1 - 3 = -4
jadi kordinat a,b,c,d berturut 2
(-3,2), (1,2), (1,-4), (-3,-4)
lebar = ab = 24 / 6 = 4
besar translasi / perpindahan = (1/2 l , 1/2 p) = (2 , 3)
Koordinat A = (-1-2, -1-3) = (-3, -4)
Koordinat B = (-1 + 2, -1 -3) = (1, -4)
koordinat C = (-1 + 2, -1 + 3) = (1, 2)
Koordinat D = (-1 - 2, -1 + 3) = (-3, 2)