diketahui : tabung
r = 21 cm
LP = 1.260π cm²
ditanya :
t?
Jawab :
LP = 1.260π
2πr(r+t) = 1.260π
2 x 21 (21 + t) = 1.260
42 (21 + t) = 1.260
21 + t = 30
t = 30 - 21
t = 9 cm
#jawaban oleh belajar bareng Okta channel
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diketahui : tabung
r = 21 cm
LP = 1.260π cm²
ditanya :
t?
Jawab :
LP = 1.260π
2πr(r+t) = 1.260π
2 x 21 (21 + t) = 1.260
42 (21 + t) = 1.260
21 + t = 30
t = 30 - 21
t = 9 cm
#jawaban oleh belajar bareng Okta channel