Diketahui :
p = 12 cm
l = 10 cm
t = 9 cm
Ditanyakan :
Luas❔
Penyelesaian :
Lp = 2(pl + pt + lt)
= 2(12 × 10 + 12 × 9 + 10 × 9)
= 2(120 + 108 + 90)
= 2(318)
= 636 cm²
Lp = 2 × ( p × ℓ + p × t + ℓ × t )
Lp = 2 × ( 12 × 10 + 12 × 9 + 10 × 9 )
Lp = 2 × ( 120 + 12 × 9 + 10 × 9 )
Lp = 2 × ( 120 + 108 + 10 × 9 )
Lp = 2 × ( 120 + 108 + 90 )
Lp = 2 × ( 228 + 90 )
Lp = 2 × 318
Lp = 636 cm²
∴Kesimpulan, jadi luas permukaan bangun ruang balok tersebut adalah 636 cm².
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Diketahui :
p = 12 cm
l = 10 cm
t = 9 cm
Ditanyakan :
Luas❔
Penyelesaian :
Lp = 2(pl + pt + lt)
= 2(12 × 10 + 12 × 9 + 10 × 9)
= 2(120 + 108 + 90)
= 2(318)
= 636 cm²
JAWABAN DENGAN CARA
Lp = 2 × ( p × ℓ + p × t + ℓ × t )
Lp = 2 × ( 12 × 10 + 12 × 9 + 10 × 9 )
Lp = 2 × ( 120 + 12 × 9 + 10 × 9 )
Lp = 2 × ( 120 + 108 + 10 × 9 )
Lp = 2 × ( 120 + 108 + 90 )
Lp = 2 × ( 228 + 90 )
Lp = 2 × 318
Lp = 636 cm²
∴Kesimpulan, jadi luas permukaan bangun ruang balok tersebut adalah 636 cm².
DETAIL JAWABAN