rivaldohasibuann
Mohon bantuannya lagi kak jawab soal kimia saya ini kak(≡^∇^≡) https://brainly.co.id/tugas/53161185?utm_source=android&utm_medium=share&utm_campaign=question
rivaldohasibuann
Mohon bantuannya lagi kak jawab soal kimia saya ini kak(≡^∇^≡) https://brainly.co.id/tugas/53161185?utm_source=android&utm_medium=share&utm_campaign=question
Penjelasan dengan langkah-langkah:
Diketahui:
Lingkaran, dengan:
Ditanyakan:
Luas daerah yang diarsir/ setengah lingkaran?
Penyelesaian:
Rumus luas setengah lingkaran: [tex]\sf \bf L = \frac{1}{2} \times Luas \ lingkaran = \frac{1}{2} \times \pi r^2 \iff \boxed {\sf \bf L = \frac{\pi r^2}{2} }[/tex], maka:
[tex]\sf \bf L = \frac{\pi r^2}{2}\\\sf \bf L = \frac{\frac{22}{7} \times 7^2}{2}\\\sf \bf L = \frac{\frac{22}{7} \times 7 \times 7}{2}\\\sf \bf L = \frac{22 \times 7}{2}\\\sf \bf L = 11 \times 7 \\\underline {\boxed {\blue {\sf \bf L = 77 \ cm^2 \ (B)}}}[/tex]
[tex] \large {\boxed {\blue {\star \:Answered \: By: \: \bold {sulkifli2018} \star} } } [/tex]
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Jawaban:
L setengah lingkaran = πr^2/2
L = πr^2/2
L = 22/7.7^2/2
L = 22/7.49/2
L = 22.7/2
L = 154/2
L = 77 cm^2
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