Diketahui
Ditanya
JAWAB
[tex] \boxed{F = B \times I \times L}[/tex]
[tex]F = 200 \: T \times 100 \: mA \times 60 \: cm[/tex]
[tex]F = 200 \: T \times ( \frac{100}{1.000} ) \: A \times ( \frac{60}{100} ) \: m[/tex]
[tex]F = 200 \: T \times 0,1 \: A \times 0,6 \: m[/tex]
[tex]F = (200 \times 0,1 \times 0,6) \: N[/tex]
[tex]F = (200 \times 0,06) \: N[/tex]
[tex]F = (2 \times 6) \: N[/tex]
[tex]F = 12 \: N[/tex]
Kesimpulan
Berdasarkan pembahasan di atas, besarnya Gaya Lorentz yang ditimbulkan sebesar 12 Newton.
KONVERSI :
100 MA = A
= 100/1.000
= 1/10
= 0,1 A
60 CM = M
= 60/100
= 3/5
= 0,6 M
MAKA :
F = (B(I(L)
= (200(0,1(0,6)
= (200(0,06)
= 12 N
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Verified answer
Diketahui
Ditanya
JAWAB
[tex] \boxed{F = B \times I \times L}[/tex]
[tex]F = 200 \: T \times 100 \: mA \times 60 \: cm[/tex]
[tex]F = 200 \: T \times ( \frac{100}{1.000} ) \: A \times ( \frac{60}{100} ) \: m[/tex]
[tex]F = 200 \: T \times 0,1 \: A \times 0,6 \: m[/tex]
[tex]F = (200 \times 0,1 \times 0,6) \: N[/tex]
[tex]F = (200 \times 0,06) \: N[/tex]
[tex]F = (2 \times 6) \: N[/tex]
[tex]F = 12 \: N[/tex]
Kesimpulan
Berdasarkan pembahasan di atas, besarnya Gaya Lorentz yang ditimbulkan sebesar 12 Newton.
KONVERSI :
100 MA = A
= 100/1.000
= 1/10
= 0,1 A
60 CM = M
= 60/100
= 3/5
= 0,6 M
MAKA :
F = (B(I(L)
= (200(0,1(0,6)
= (200(0,06)
= 12 N