LOGARYTMY !
A) log⅓ 4 + log⅓ 6 - log⅓ 8 = ... > ma wyjść -1.
B) log⅔ 4 - 2log⅔ 3 = ... > ma wyjść 2.
proszę o jak najszybsze rozwiązanie ! ;-) i wytłumaczenie co, jak i skąd się to wzięło ... ?
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a)
log 1/3 [ 4 ] + log 1/3 [6 ] - log 1/3 [ 8 ] =
= log 1/3 [ 4*6] - log 1/3 [ 8] =log 1/3 [ 24] - log 1/3 [ 8] =
log 1/3 [ 24 : 8 ] = log 1/3 [ 3 ] = - 1 ,
bo ( 1/3)^(-1) = 3
b)
log 2/3 [ 4 ] - 2 log 2/3 [ 3 ] = log 2/3 [ 4 ] - log 2/3 [ 3^2 ] =
= log 2/3 [ 4 ] - log 2/3 [ 9 ] = log 2/3 [ 4 : 9] = log 2/3 [ 4/9 [ =
= 2,
bo ( 2/3) ^ 2 = 4/9