September 2018 2 16 Report
×^log(5x-3) + ×^log4= 2

Ini gimana pengerjaannya ya??
Menurut guru sih begini....

×^log(5x-3) + ×log4= 2
×^log(5x-3).4 = ×^logx^2
(5x-3).4 = x^2
x^2 - 20x + 12= 0

Tinggal nyari nilai x nya aja.
Mohon bantuannya.
Pusing tadi UTS gk bisa ngerjakannya.


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