log₁₇1 = x
log₆∛36 = x [to 36 jest pod tym pierwiastkiem szescienny]
Prosze o rozwiązanie tych logarytmów.
17^x = 1 (^x - podnieść do potęgi x)
x = 0
log₆∛36 = x
6^x = ∛36
6^x = [(6)^2]^1/3
6^x = 6^ 2/3
x = 2/3
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log₁₇1 = x
17^x = 1 (^x - podnieść do potęgi x)
x = 0
log₆∛36 = x
6^x = ∛36
6^x = [(6)^2]^1/3
6^x = 6^ 2/3
x = 2/3