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lim (t->3) ( t²- t-6)( 4 +√(5t+1)) /(4- √(5t+1))(4+√(5t+1))
lim (t->3) [ (t-3)(t+2)(4 +√(5t +1) ] / [16 - (5t+1))
lim(t->3) [ (t-3)(t+2)(4 + √(5t+1) ] / (15-5t)
lim(t->3) [ (t-3)(t+2)(4 +√(5t+1)] / -5(t - 3)
lim(t->3) (t+2)(4 +√(5t+1)) / - 5
t = 3 --> (5)(4+4)/(-5) = - 16