liczby 6, x, y, 12 tworzą ciąg arytmetyczny. oblicz x i y.
Jeśli by było to poproszę również o wytłumaczenie.
a1 = 6a4 = 12a4= a1+3r12= 6 + 3r6 = 3rr = 2a2 = a1+ra2 = 6+ 2 = 8a3 = a1+2ra3 = 6+ 4a3 = 10ciąg : 6,8,10,12
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a1 = 6
a4 = 12
a4= a1+3r
12= 6 + 3r
6 = 3r
r = 2
a2 = a1+r
a2 = 6+ 2 = 8
a3 = a1+2r
a3 = 6+ 4
a3 = 10
ciąg : 6,8,10,12