Liczby 3x+1, x+1 , x2- 1 są kolejnymi wyrazami rosnącego ciągu arytmetycznego. Wyznacz te liczby.
3x+1, x+1 , x2- 1
a1 a2 a3
a3 - a2 = a2 - a1
x² - 1 - (x + 1) = x + 1 - (3x +1)
x² - 1 - x - 1 = x + 1 - 3x - 1
x² - x - 2 = -2x
x² - x + 2x - 2 = 0
x² + x - 2 = 0
Δ = 1² - 4 * 1 * (-2) = 1 + 8 = 9
√Δ = 3
x1 = (-1 - 3)/2 = -4/2 = -2
x2 = (-1 + 3)/2 = 2/2 = 1
odp. x = -2
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3x+1, x+1 , x2- 1
a1 a2 a3
a3 - a2 = a2 - a1
x² - 1 - (x + 1) = x + 1 - (3x +1)
x² - 1 - x - 1 = x + 1 - 3x - 1
x² - x - 2 = -2x
x² - x + 2x - 2 = 0
x² + x - 2 = 0
Δ = 1² - 4 * 1 * (-2) = 1 + 8 = 9
√Δ = 3
x1 = (-1 - 3)/2 = -4/2 = -2
x2 = (-1 + 3)/2 = 2/2 = 1
odp. x = -2