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3b=bc|÷ b a₂=a₁+r a₅=a₁+4r
3=c b=3+r c=3+4r
r=b-3 4r=c-3 |÷4
0=b-3 r=¼c - ¾
b=3 r=¼×3 -¾=¾-¾=0
odpowiedź: b=3 ; c=3