liczby 2 , x-3, 8 w podanej kolejności pierwszym, drugim i czwartym wyrazem ciągu arytmetycznego. oblicz x.
a₁=2
a₂=x-3
a₄=8
a_n=a₁+(n-1)r
a₂=2+(2-1)r
a₄=2+(4-1)r
8=2+(4-1)r
8=2+3r
3r=6
r=2
x-3=2+(2-1)r
x-3=2+(2-1)*2
x-3=2+2
x=7
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a₁=2
a₂=x-3
a₄=8
a_n=a₁+(n-1)r
a₂=2+(2-1)r
a₄=2+(4-1)r
8=2+(4-1)r
8=2+3r
3r=6
r=2
a₂=2+(2-1)r
x-3=2+(2-1)r
x-3=2+(2-1)*2
x-3=2+2
x=7