liczba pierwiastkow wielomianu W(x)=(x+1)(3-x)(x2-9) jest rowna
x = -1
x = 3
x =-3
odpowiedź : x = {-3, -1, 3}
W(x)=(x+1)(3-x)(x2-9)
x+1=0
x=-1
3-x=0
-x=-3 /:(-1)
x=3
x2-9=0
∆ = 0-4*1*(-9)=36
√∆ = 6
x1 = -6/2 = -3
x2 = 6/2 = 3
Różnych pierwiastków jest 3 x(-3, -1, 3)
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x = -1
x = 3
x =-3
odpowiedź : x = {-3, -1, 3}
W(x)=(x+1)(3-x)(x2-9)
x+1=0
x=-1
3-x=0
-x=-3 /:(-1)
x=3
x2-9=0
∆ = 0-4*1*(-9)=36
√∆ = 6
x1 = -6/2 = -3
x2 = 6/2 = 3
Różnych pierwiastków jest 3 x(-3, -1, 3)