Odpowiedź:
(2^(3/2)-2^(1/2))^(1/2)=2^(1/4)
Szczegółowe wyjaśnienie:
[tex](2^{\frac{3}{2}}-2^{\frac{1}{2}})^{\frac{1}{2}}=(\sqrt{2^3}-\sqrt2)^\frac{1}{2}}=(\sqrt{8}-\sqrt2)^\frac{1}{2}}=(2\sqrt{2}-\sqrt2)^\frac{1}{2}}=(\sqrt{2})^\frac{1}{2}}=\sqrt[4]{2} =2^{\frac{1}{4}}[/tex]
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Odpowiedź:
(2^(3/2)-2^(1/2))^(1/2)=2^(1/4)
Szczegółowe wyjaśnienie:
[tex](2^{\frac{3}{2}}-2^{\frac{1}{2}})^{\frac{1}{2}}=(\sqrt{2^3}-\sqrt2)^\frac{1}{2}}=(\sqrt{8}-\sqrt2)^\frac{1}{2}}=(2\sqrt{2}-\sqrt2)^\frac{1}{2}}=(\sqrt{2})^\frac{1}{2}}=\sqrt[4]{2} =2^{\frac{1}{4}}[/tex]