liczbę 64 do potengi -5 przedstaw w postaci potengi o podanej podstawie
a)2
b)4
c)8
* potęgi :D
a)
b)
c)
a) 64^-5 =(2^6)^-5=2^(6*(-5))=2^-30
b)6 4^-5 = (4^3)^-5=4^(3*(-5))=4^-15
c) 64^-5=(8^2)^-5=8^(2*(-5))=8^-10
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* potęgi :D
a)
b)
c)
a) 64^-5 =(2^6)^-5=2^(6*(-5))=2^-30
b)6 4^-5 = (4^3)^-5=4^(3*(-5))=4^-15
c) 64^-5=(8^2)^-5=8^(2*(-5))=8^-10