\left \{ {{(x-4)(x+2)+2y=x(x-3)-3} \atop {(y-1)(y+1)-3x=y(y+4)-12}} \right.
rozwiąz uklad
x²-4x+2x-8 +2y = x²-3x -3
y² -1 -3x =y²+4y -12
x²-x²-4x+2x+3x+2y=-3+8
y²-y²-3x-4y=-12+1
x+2y=5 /*3
-3x-4y=-11
3x+6y=15
2y=4 /:2
y=2
x+2y=5
x+4=5
x=1
odp:
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x²-4x+2x-8 +2y = x²-3x -3
y² -1 -3x =y²+4y -12
x²-x²-4x+2x+3x+2y=-3+8
y²-y²-3x-4y=-12+1
x+2y=5 /*3
-3x-4y=-11
3x+6y=15
-3x-4y=-11
2y=4 /:2
y=2
x+2y=5
x+4=5
x=1
odp:
x=1
y=2