Lebar suatu persegi pnjang sepertiga dari panjangnya.jika keliling persegi panjang 56cm, maka luas persegi panjang tersebut adlah a.126 b.147 c.243 d.588
Fayshal
Lebar = x Panjang = 3x Keliling = 2 (p+l) 56 = 2 (p+l) (p+l) = 56/2 = 28 cm x + 3x = 28 4x = 28 x = 28/4 x = 7 jadi lebar = x = 7 cm panjang = 3x = 3 x 7 = 21 cm Maka luas = panjang x lebar = 21 x 7 = 147 (b)
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haulaa
L = 1/3p k = 56 k = 2(p+l) 56=2(p + 1/3p) 56/2=3p/3+ 1p/3 28 = 4p/3 28 × 3 = 4p 84 = 4p p = 84/4 p = 21
Panjang = 3x
Keliling = 2 (p+l)
56 = 2 (p+l)
(p+l) = 56/2 = 28 cm
x + 3x = 28
4x = 28
x = 28/4
x = 7
jadi lebar = x = 7 cm
panjang = 3x = 3 x 7 = 21 cm
Maka luas = panjang x lebar = 21 x 7 = 147 (b)
k = 56
k = 2(p+l)
56=2(p + 1/3p)
56/2=3p/3+ 1p/3
28 = 4p/3
28 × 3 = 4p
84 = 4p
p = 84/4
p = 21
luas = p × l
= 21 × 1/3(21)
= 21 × 7
=147 (B)