Layang-layang KLMN, luasnya 297 cm2. Panjang KO 11cm sedangkan NO:OL=4:5. Tentukan panjang NO dan OL berturut - turut ?
5dregensleyer
Km = 11 x 2 = 22 D₂ = ( 4a + 5a) = 9a luas = D₁ x D₂ : 2 297 = 22 x 9a : 2 297 = 11 x 9a 297 = 99a 297/99 = a 3 = a maka pajang masing-masing NO = 4 x 3 = 12 cm OL = 5 x 3 = 15 cm
= 22
D₂ = ( 4a + 5a)
= 9a
luas = D₁ x D₂ : 2
297 = 22 x 9a : 2
297 = 11 x 9a
297 = 99a
297/99 = a
3 = a
maka pajang masing-masing
NO = 4 x 3 = 12 cm
OL = 5 x 3 = 15 cm
1/2 x Da x Db = 297
km x NL = 297 x 2
22cm x NL = 594
NL = 594/22 = 27cm
No : Ol = 4x : 5x
No+OL = NL
4x+5x = 27
9x = 27
x= 27/9= 3
No= 4x = 4(3) = 12cm
OL = 5x= 5(3) = 15cm