Question

Layang layang ABCD memiliki panjang diagonal BD=28 cm dan BO:OD=2:5. Hitunglah
A.panjang diagonal AC,jika panjang AB=10cm
B.luas layang layang ABCD!

Answer 1

BO = 2/7 X 28 = 8cm
OD = 5/7 x 28 = 20cm
AB = 10cm
maka AO = 8cm (Tripel Pythagoras 6-8-10)
Panjang diagonal AC = 2AO = 2 X 8 = 16cm

B. Luas = acxbd/2 = 16 x 28/2 = 224cm²

Answer 2

Panjang BO = × 28 = 8 cm
panjang AO = 6 cm -> dari tripel pythagoras 6,8,10 yang dasarnya 3,4,5
panjang AC = 2×AO = 2×6 = 12
L = 1/2 × d1 × d2
= 1/2 × 24 × 28
= 236 cm²

**maaf kalau salah