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H+ = 2 x 10^-5
H+ = Ka (asam lemah/Basa konjugasi )
2x10^-5 = 10^-5 (CH3COOH/CH3COO-)
2 CH3COO- = CH3COOH
2/1 = CH3COOH/CH3COONa
CH3COONa ⇒ CH3COO- + Na+ (CH3COO- = CH3COONa krn perbndingan koef 1/1)
2 2 2
perbandinganya yaitu 2:1