Question

Larutan X(OH)2 mempunyai ph=8-log 2,maka hasil kali kelarutan X(OH)2 adalah.tolong bantu soal kimia ini

Answer 1

[H+]= 2 x 10 ^-8
[OH-] = 10^-14/2x10^-8=5x10^-7
X(OH)2➡X ^2+ 2[OH-]
s s 2s
s dari X=1/2x5x10^-7=2,5x10^-7
Ksp=[X^2+][OH-]^2
=(2,5x10^-7)(5X10^-7)^2
=(25x10^-8)(25x10^-14)
=625x10^-22
=6,25 x 10^-20