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pH = 2 ---- maka, [H⁺]₁ = 10⁻² M
V₂ = 1000 cm³
Dit : pH = ......? setelah pengenceran.
Jwb: [H⁺]₂ x V₂ = [H⁺]₁ x V₁
[H⁺]₂ x 1000 = 10⁻² x 100
[H⁺]₂ = 10⁻³ M
pH = -log [H⁺]²
= - log 10⁻³
pH = 3