Question

(lanjutan)
Jika α dan β akar-akar persamaan 3x²+x+2=0 maka hitunglah soal diatas​​

Answer 1

Verified answer

Penjelasan dengan langkah-langkah:

3x² + x + 2 = 0

a = 3

b = 1

c = 2

a. a²b + ab²

= a(ab) + b(ab)

= (a + b) . ab

= (-b/a) . (c/a)

= (-1/3) . (2/3)

= -1/3 . 2/3

= -2/9

b. 1/(a + 1) + 1/(b + 1)

= (1(b + 1) + 1(a + 1))/(a + 1)(b + 1)

= (b + 1)+ (a + 1)/(a + 1)(b + 1)

= (a + b + 2)/(ab + a + b + 1)

= (-b/a + 2)/(c/a + (-b/a) + 1)

= (-1/3 + 2)/(2/3 - 1/3 + 1)

= (5/3)/(4/3)

= 5/4