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Mr HCL = 36,5
misalkan saja massa larutan = 1015 gram, maka :
m HCl = × 1015 gr = 204,015 gr
Lalu hitung n HCl :
n HCl = m / Mr = 204,015 gr / 36,5 = 5,59 mol
Hitung Volume larutan :
V = m / ρ = 1015 gr / 1,015 gr/mL = 1000 mL = 1 L
Hitung Konsentrasi HCl dalam larutan
M = n / V = 5,59 mol / 1L = 5,59 M ≈ 5,6 M