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x + y = 1/3 ( 10x + y)
x - 5 = y
Sl2
u es unidades
d es decenas
d + u = (10d + u) / 3 (1)
u = d + 5 (2)
se reemplaza (2) en (1)
d + u = (10d + d + 5) / 3 (1)
d + (d + 5) = (10d + d + 5) / 3
2d + 5 = (11d + 5) / 3
3(2d + 5) = 11d + 5
6d + 15 = 11d + 5
5d = 15 - 5
5d = 10
d = 10/5
d = 2 (4)
se reemplza (4) en (2)
u = d + 5 (2)
u = 2 + 8
u = 7
u = 7
d = 2
se comprueba para verificar la validez del resultado
d + u = (10d + u) / 3 (1)
2 + 7 = (10(2) + 7) / 3
9 = (20 + 7) / 3
9 = 27/3
9 = 9
u = 7, respuesta
d = 2, respuesta
Espero te sirva