La suma de dos cifras de un numero es 12 si al producto de ellas se le suma 66 se obtiene el primer numero con sus cifras invertidas ¿cual es el numero?
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a+b=12
axb + 66 = ba = 10xb + a = 9xb + (a+b) = 9.b + 12
66 - 12 = 9.b - a.b = 54
(9 - a) x b = 54 =6 x 9
9 - a = 6
a = 3
b = 9
rpt. ab = 39