la suma de cinco numeros impares consecutivos es mayor que 2012
cual es el menor valor posible de esta suma.
sean los numeros impares consecutivos
x-3
x-1
x+1
x+3
x+5
x-3+x-1+x+1+x+3+x+5>=2012
S=5x+5>=2012
5x>=2007
x>=401.4
xmax=402
smax=5x+5=5*402+5=2015
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sean los numeros impares consecutivos
x-3
x-1
x+1
x+3
x+5
x-3+x-1+x+1+x+3+x+5>=2012
S=5x+5>=2012
5x>=2007
x>=401.4
xmax=402
smax=5x+5=5*402+5=2015
x-3
x-1
x+1
x+3
x+5
x-3+x-1+x+1+x+3+x+5>=2012
S=5x+5>=2012
5x>=2007
x>=401.4
xmax=402
smax=5x+5=5*402+5=2015