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Resolvemos :
x + x + 1 + x + 2 + x + 3 = 124
x + x + x + x + 1 + 2 + 3 = 124
4x + 6 = 124
4x = 124 - 6
4x = 118
x = 118/4
x = 29.5
No existe tales números consecutivos cuya suma sea = 124
x+x+1+x+2+x+3 = 124
4x + 6 = 124
4x = 124 - 6
4x = 118
x = 118/4
x = 29,5 Pero la pregunta seria quien es el consecutivo de 29,5