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-b + o - √b²-4ac
2(a)
x²+2x+1=0
donde a=1 b=2 c=1
-2 + o - √2²-4(1)(1) ..........-2 + o - √4-4 .......-2 + o - √0 .....-2 + o - 0
2(1) 2 2 2
x= -2......x=1
2
en este caso tenemos solucion unica x= -1
.........................................
x²+2x-15=0
b + o - √b²-4ac
2(a)
a=1 b=2 c= -15
-2 + o - √2²-4(1)(-15) ......-2 + o - √4+60 ......-2 + o - √64 ....-2 + o - 8
2(1) 2 2 2
soluciones
x= -2 + 8 ........x= 6 ........x=3
2 2
x= -2 -8 ........x= -10 .......x= -5
2 2
x=3 x= -5
.....................................
-3x²+15x-18=0
b + o - √b²-4ac
2(a)
a= -3 b=15 c= -18
-15 + o - √(15)²-4(-3)(-18) .....-15 + o - √225-216 .....-15 + o - √9
2(-3) -6 -6
-15 + o - 3
-6
soluciones
x= -15 - 3 ......x= -18 ......x=3
-6 -6
x= -15 + 3 ....x= -12 .....x=2
-6 -6
x=3 x=2