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[H+]=4 .10^-3 mol/L
a=4.10^-2 M
dit: Ka dan α=..?
[H+]=√Ka.a
(4.10^-3)2=Ka.4.10^-2
16.10^-6=Ka.4.10^-2
Ka=16.10^-6/4.10^-2
Ka=4.10^-4
α=√Ka/a=√4.10^-4/4.10^-2=√10^-2=0,1