Question

Larutan H2SO4 pekat 98% sebanyak 1,8 mL , massa jenis 1,8 kg/L dilarutkan dalam 200 mL air , brapa ph ny ?

Answer 1

M1 = p x 10 x kadar / Mr
= 1,8 x 10 , 98 / 98
= 18
V1 X M1 = V2 X M2
1,8 X 10 ^ -3 X 18 = 0,2018 X M2
32,4 X 10^ -3 = 2 X 10 ^ -1 X M2
M2 = 16,2 X 10^ -2

[H+] = 16,2 X 10^ -2 X 2
= 32,4 X 10^ -2 M

pH = - log [H+]
= - LOG 32,4 X 10^ -2
= 2 - LOG 32,4