Do jakiej objetosci wody nalezy dodac 170ml r-ru HCl o stezeniu 0,53mol/l aby otrzymac roztwor 0,1 molowy
0,17dm3 0,53M..........................0,1
..........................0,1M
xdm3 OM.................................0,53-0,1=0,43
0,17/x = 0,1/0,43
0,1x = 0,0731
x = 0,731dm3
x = 731ml wody
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
0,17dm3 0,53M..........................0,1
..........................0,1M
xdm3 OM.................................0,53-0,1=0,43
0,17/x = 0,1/0,43
0,1x = 0,0731
x = 0,731dm3
x = 731ml wody